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Re: simplifying a summation / integral

  • To: mathgroup at smc.vnet.net
  • Subject: [mg64851] Re: simplifying a summation / integral
  • From: Peter Pein <petsie at dordos.net>
  • Date: Sun, 5 Mar 2006 03:19:30 -0500 (EST)
  • References: <dubjgg$gpp$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Patrik schrieb:
> Jean, Paul:
> 
> Thanks for your comments.
> 
> Yes I tried those and got the hypergeometricPFQ functions. But, I need to take the derivative of the summation and hence do not mind making approximations if that helps get a simple looking derivative (the derivative is part of a first order condition and hence I've to substitute the derivative in an equation & solve for x). The hypergeometricPFQ is not suited for that.
> 
> Thanks,
> Kartik
> 
> Thanks,
> Kartik
> 
Hi, Patrik or Kartik,

may I cite your OP?
I know that the above expression is the same as
Integral[((1+x)^q - 1)/x]

So de derivative should equal ((1+x)^q-1)/x.

Does this expression suit your needs?

If not, I'm totally confused, sorry.

Peter


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