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Re: laplace transform

  • To: mathgroup at
  • Subject: [mg65144] Re: laplace transform
  • From: Paul Abbott <paul at>
  • Date: Wed, 15 Mar 2006 06:30:36 -0500 (EST)
  • Organization: The University of Western Australia
  • References: <dv68hj$nvj$>
  • Sender: owner-wri-mathgroup at

In article <dv68hj$nvj$1 at>,
 Marlies.Goorden at wrote:

> I have a problem with the Laplace transform of mathematica. I 
> want to know the laplace transform of sin(a*t).
> When I type
> LaplaceTransform[sin(a*t),t,s]
> mathematica gives me
> \sqrt(a^2) sign(a)/(a^2+s^2)
> On the other hand my mathematics books gives the answer
> a/(s^2+a^2)
> For complex a the answer is not the same. If I choose for 
> example 
> a=0.3+0.5i and
> s=1
> the two formulas give me 
> -0.096+0.65i and 0.51+0.41i respectively.
> A numerical integration,
> i.e. NIntegrate[Sin((0.3+0.5i)*t)*Exp[-t],{t,0,Infinity}]
> gives me the same numerical value as the mathematics book 
> formula.
> Is the mathematica formula wrong?

Yes and no. LaplaceTransform is making assumptions that are incompatible 
with a being complex. If you enter

  LaplaceTransform[Sin[a t], t, s, 
   GenerateConditions -> True, Assumptions -> NotElement[a,Reals]]

you get a/(s^2+a^2). Alternatively, if you put a -> x + I y then you 
will get the answer that you desire:

  LaplaceTransform[Sin[(x + I y) t], t, s]


Paul Abbott                                      Phone:  61 8 6488 2734
School of Physics, M013                            Fax: +61 8 6488 1014
The University of Western Australia         (CRICOS Provider No 00126G)    

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