Re: Bug with Series[] - help wanted
- To: mathgroup at smc.vnet.net
- Subject: [mg65411] Re: [mg65394] Bug with Series[] - help wanted
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Fri, 31 Mar 2006 06:09:04 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
To enter the input 1+1/r+O((1/r)^2), use
Series[1+1/r,{r,Infinity,1}]
Another example,
Series[1/(r+1),{r,Infinity,3}]//Simplify
%//Normal
Series[%,{r,Infinity,3}]
Bob Hanlon
>
> From: "GidiL" <gidienator at gmail.com>
To: mathgroup at smc.vnet.net
> Subject: [mg65411] [mg65394] Bug with Series[] - help wanted
>
> Hello all!
>
> I would really appreciate some help.
>
> Mathematica has a built-in function called Series:
> Series[x,x_0,n],
> which allows to expand functions into power series where x is the
> variable, x_0 is the point about which we expand, and n is the desired
> order of expansion.
>
> It also allows x_0 to be infinity, which is very useful when one needs
> multiple expansion (as in gravitational waves and electromagnetic
> radiation).
>
> Although is allows to expand series in terms of 1/x and writes O(1/x)
> (and its powers) in the output, it does not allow this to be entered in
> the input. To convince yourselves, try it out. Enter in the input,
> e.g., 1+ 1/r+ (O(1/r))^2, and it will tell you that 1/r is not a
> variable.
>
> If, on the other hand, you entered:
> In=Series[1/(r+1), {r, Infinity,3}]//Simplify
> you will get
> Out=1/r-(1/r)^2+(1/r)^3+(O(1/r))^4
>
> which shows that the output is possible, but the input is impossible.
>
> Can anyone offer some assistance?
>
> Thanks,
> Gideon
>
>