Re: use a function within a new function
- To: mathgroup at smc.vnet.net
- Subject: [mg70941] Re: use a function within a new function
- From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
- Date: Thu, 2 Nov 2006 06:47:40 -0500 (EST)
- Organization: Uni Leipzig
- References: <ei9nuo$1ps$1@smc.vnet.net>
Hi,
you can't because the region you are ploting is in
the first
case {{t, 0, 9}, {a, 0, 9}}
in the second one {t, 0, 720}, {a, 0, 720}
and you see the difference of a magnification
factor 80
while you will have no problems with an ant, when
you magnify
the ant by a factor of 80 it *will* look
different.
Regards
Jens
<aitor69gonzalez at gmail.com> schrieb im Newsbeitrag
news:ei9nuo$1ps$1 at smc.vnet.net...
| Hello,
|
| I have a function like:
| phi(a,t) = sin(2*pi*(t-a)/T' + a/T)
| where "T" is itself a function of "a" like here:
| ####
| Plot3D[Sin[2*\[Pi]*((t - a)/3 + a/(a + 1))], {t,
0, 9}, {a, 0, 9},
| AxesLabel -> {"t", "a", "ex"}, Lighting ->
False,
| ViewPoint -> {0, 0, 100}, PlotPoints -> 40,
Mesh -> False];
| ####
| Therefore, I would like to define T separately.
Something like here:
| ####
| T[a_] = a + 1;
| phi[a_, t_] = Sin[2*\[Pi]*((t - a)/3 + a/T[a])];
| Plot3D[phi[a, t], {t, 0, 720}, {a, 0, 720},
AxesLabel -> {"t", "a",
| "ex"},
| Lighting -> False, ViewPoint -> {0, 0, 100},
PlotPoints -> 40,
| Mesh -> False]
| ####
| But as you can see, both plots do not look like
the same. How can I
| define a "T" as a function of a separately?
| Thank you in advance.
|
| Aitor
|