SetPrecision vs N
- To: mathgroup at smc.vnet.net
- Subject: [mg71683] SetPrecision vs N
- From: "Andrew Moylan" <andrew.j.moylan at gmail.com>
- Date: Sun, 26 Nov 2006 03:49:19 -0500 (EST)
Hi all, Suppose I want to evaluate an expression at a given precision. What is the difference between using N[expr, precision] and using SetPrecision[expr, precision]? I've noticed that SetPrecision seems to be equivalent even in such situations as e.g. N[Integrate[...]] automatically calling NIntegrate[...] when the integral can't be done exactly: SetPrecision[Integrate[x^x, {x, 0, 1}], 20] and N[Integrate[x^x, {x, 0, 1}], 20] both give 0.78343051071213440706 Are there important differences between SetPrecision and N that I should be aware of? Cheers, Andrew
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