Re: On partitioning lists by intervals
- To: mathgroup at smc.vnet.net
- Subject: [mg80446] Re: On partitioning lists by intervals
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Wed, 22 Aug 2007 04:54:33 -0400 (EDT)
- Organization: Uni Leipzig
- References: <faea5n$ejf$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
if you need a fixed length of the sub lists
lst=Table[Random[],{100}];
Partition[Sort[lst],10]
will help. But this is different from
"I need to get sublists of values that go from 0 to
> 10, 10 to 20, etc"
BinCounts[lst,{0,1,0.1}]
Regards
Jens
Mauricio Esteban Cuak wrote:
> Hello there.
> I'm just starting in mathematica and I realise this is a very basic
> question, but I tried to find an answer on the documentation center
> for a couple of hours and on the archive for mathgroup, but couldn't
> find it.
> I have a list of say 500 different random values. I need to divide it
> in n intervals of fixed length (for example, the lowest value is 0 and
> the maximum 100 so I need to get sublists of values that go from 0 to
> 10, 10 to 20, etc.)
> Thanks for your help!
>
> cd
>