Re: expressions list -> equations list
- To: mathgroup at smc.vnet.net
- Subject: [mg83979] Re: expressions list -> equations list
- From: Szabolcs Horvát <szhorvat at gmail.com>
- Date: Thu, 6 Dec 2007 02:39:34 -0500 (EST)
- References: <fj6404$em9$1@smc.vnet.net>
Hauke Reddmann wrote:
> 1st of all THX to all who answered my last question. Just one other before
> I lend a Mathematica manual from the public lib and pester you no more :-)
>
> So. Now that I have a tensor it must vanish identically. I Flatten[] it first
> and then I have a list of equations...oh, stop, I haven't. REDUCE (if I may
> mention the name of a competition :-) could take a Solve[] now because it
> automatically assumes a "=0" as default but Mathematica is anally-retentive
> (a good thing :-) and I somehow must turn {a,b,c} into {a=0,b=0,c=0}.
> Convert to string, global change "," -> "=0," and "}" -> "=0}", reconvert
> to list? Is that possible? Or is there a less LISP-hack-style solution?
>
Note that in Mathematica a = 0 is an assignment. If you need to assign
values to several undefined symbols, then
{a, b, c} = {0, 0, 0}
will work. If you need to build a list of equations then try
# == 0 & /@ {a, b, c} or Thread[{a,b,c} == 0]
both of which yield {a==0, b==0, c==0}
But Solve[] seems to accept vector-equations too:
In[1]:= Solve[{a, b, c} == 0, {a, b, c}]
Out[1]= {{a -> 0, b -> 0, c -> 0}}
In[2]:= Solve[{a, b, c} == {1, 2, 3}, {a, b, c}]
Out[2]= {{a -> 1, b -> 2, c -> 3}}
If it doesn't work for some reason, then use Thread[]:
In[3]:= Thread[{a, b, c} == {1, 2, 3}]
Out[3]= {a == 1, b == 2, c == 3}
--
Szabolcs