Re: graphing traces of complicated evaluations (improved)
- To: mathgroup at smc.vnet.net
- Subject: [mg79244] Re: graphing traces of complicated evaluations (improved)
- From: chuck009 <dmilioto at comcast.com>
- Date: Sat, 21 Jul 2007 04:42:17 -0400 (EDT)
Suppose I'm tenacious. Really I'm just not satisfied with Integrate returning Pi^2/6 for this integral. I know it's a bug but aren't they just curious why it's giving this answer?
In[15]:=
Integrate[Log[1 + Exp[-z]/Sqrt[z]], {z, 0, Infinity}]
Out[15]=
Pi^2/6
I tried using your code to trace it but to no avail. Any suggestions?
> Previously, I released code that could help with the
> tracing of
> evaluations,