Re: Re: Means
- To: mathgroup at smc.vnet.net
- Subject: [mg73970] Re: [mg73939] Re: Means
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 3 Mar 2007 23:51:40 -0500 (EST)
- Reply-to: hanlonr at cox.net
Mean[Drop[list, IntegerPart[Length[list]/2]][[All, 2]]]
Bob Hanlon
---- "JGBoone at gmail.com" <JGBoone at gmail.com> wrote:
> Yeah Bob that line you gave me does the same as N[Mean[Map[Last,
> list]]]. It goes to the second part of the pair and takes the average
> of all. I want to take only the average of the last half of the last
> half. So i have 3000 pairs that look like {a,b}
> i've got a way to take the means of all the b's in list of 3000. but i
> want to take the mean's of the last 1500 b's.