Re: Factorizing...
- To: mathgroup at smc.vnet.net
- Subject: [mg74119] Re: Factorizing...
- From: Peter Pein <petsie at dordos.net>
- Date: Mon, 12 Mar 2007 04:31:24 -0500 (EST)
- References: <esr0lj$6hp$1@smc.vnet.net> <esu5qh$riq$1@smc.vnet.net> <et0no6$mq4$1@smc.vnet.net>
Bruno Campanini schrieb: > "Jean-Marc Gulliet" <jeanmarc.gulliet at gmail.com> wrote in message > news:esu5qh$riq$1 at smc.vnet.net... > >> Using the correct syntax strongly helps. See " The Mathematica Book >> Online / A Practical Introduction to Mathematica / Numerical >> Calculations / 1.1.3 Some Mathematical Functions" at >> http://documents.wolfram.com/mathematica/book/section-1.1.3 >> >> In[1]:= >> Simplify[Factor[2 + Sqrt[5]] == ((1 + Sqrt[5])/2)^3] >> >> [...disregard the warning message...] >> >> Out[1]= >> True > > I don't want to get that. > I would like to have: > > In[1]= > Factor[2 + Sqrt[5]] > > Out[1]= > ((1 + Sqrt[5])/2)^3 > > instead of > > Out[1]=2 + Sqrt[5] > > Bruno > > Hi Bruno, try RootReduce: (2 + Sqrt[5])^(1/3) // RootReduce --> (1/2)*(1 + Sqrt[5]) Factor can not guess, wether you want sth.^3 or for instance Expand[Sqrt[1/2 + Sqrt[5]/2]^6] --> 2 + Sqrt[5] hth, Peter