Re: Noob evaluation question
- To: mathgroup at smc.vnet.net
- Subject: [mg74168] Re: Noob evaluation question
- From: Bill Rowe <readnewsciv at sbcglobal.net>
- Date: Tue, 13 Mar 2007 03:41:03 -0500 (EST)
On 3/12/07 at 10:08 PM, heycarnut at gmail.com (heycarnut) wrote:
>Given :
>Position[{1, 2, 3, 4, 5, 6, 7, 8, 9}, _?(# <= Random[Integer, {1,
>9}] &)]
>How can we make the generated random number 'fixed' for the
>evaluation of Position, instead of a new number getting generated at
>each element of the list (the above is a simplified and contrived
>example.)
If you are going to use Position in this manner, the way to do
what you want is as follows:
m=Random[Integer, {1, 9}];
Position[{1, 2, 3, 4, 5, 6, 7, 8, 9}, _?(# <= m&)]
But this is rather inefficient
More efficient would be
Range[Random[Integer, {1,9}]]
Or if you need a n X 1 array
List/@Range[Random[Integer, {1,9}]]
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