Re: Boundary Conditions in PDE
- To: mathgroup at smc.vnet.net
- Subject: [mg74350] Re: Boundary Conditions in PDE
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Mon, 19 Mar 2007 02:08:04 -0500 (EST)
- References: <etik9a$j4q$1@smc.vnet.net>
Hi,
and
Derivative[1,0][F][0,t]
does not work ??
Regards
Jens
bar at ANTYSPAM.ap.krakow.pl wrote:
> I have a problem with defining boundaru conditions id NDSolve
> of PDE
> F is function of [x,t]
> Conditions has form : (d/dx)F[0,t]==0;
>
> I wrote this in form : D[F[0,t],x]==0
> Its TRUE (0==0)
>
> Then i wrote D[F[x,t],x]
> out: F(1,0)[x,t] ; {(1,0) looks like "power"}
>
> And "copy"&"paste", and changed x to 0 in arguments
>
> This way works, but I'm sure is a better way ?
>
> Regards, Olaf
>
>