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Re: About function to evaluation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg74482] Re: [mg74473] About function to evaluation
  • From: bsyehuda at gmail.com
  • Date: Fri, 23 Mar 2007 18:58:30 -0500 (EST)

Hi
modify the function f for simplicity
f[x_,y_]:={x,y,2x+3y}
and then
data={{1,2,0},{2,3,0},{4,1,0},{6,3,0},{1,3,0}}
and
myResult=(f@@Reverse[Most[#]])&/@data
generate the list and
TableForm[myResult,TableHeadings\[Rule]{None,{"x","y","f[x,y]"}},
    TableAlignments\[Rule]Center]
generates the table

yehuda


On 3/22/07, Evanescence <origine26 at yahoo.com.tw> wrote:
>
> Hello Dear all:
> My questions are as follows:
> First I definite a function is f[x_,y_]:=2x+3y
> Then I have a list is data={{1,2,0},{2,3,0},{4,1,0},{6,3,0},{1,3,0}}
> For example{y,x,z}={1,2,0}    {y,x,z}={2,3,0}  {y,x,z}={4,1,0}
> {y,x,z}={6,3,0} {y,x,z}={1,3,0}
> I want to take the list data to the function to get the function
> values.
> Then express the form as follows at last
>
>    x     y     f[x,y]
>    2     1       7
>    3     2      12
>    1     4      14
>    3     6      24
>    3     1       9
>
> PS: The z values is zero overall.
> Please tell me how to get the function values in the list
> Thank you very much
> Evanescence 2007 03 21
>
>
>


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