Re: Thread function now working as expected
- To: mathgroup at smc.vnet.net
- Subject: [mg74603] Re: Thread function now working as expected
- From: dh <dh at metrohm.ch>
- Date: Wed, 28 Mar 2007 01:38:48 -0500 (EST)
- References: <euan64$do9$1@smc.vnet.net>
Hi, Thread is an ordinary function and its arguments are evaluated. Therefore, Expand[eqn2] does nothing and returns eqn2, what is then fed to Thread. Having said this, what you want can be achieved e.g. by mapping Expand over eqn2: Expand/@eqn2 Daniel siewsk at bp.com wrote: > I cannot get the Thread function to work on In[3] and I > am forced to do it manually in In[4] > > Does anyone has any idea why In[3] is not working as I expected? > > In[1]:= eqn1 = Sqrt[1 + 196*x^4] == 12*x - 1 - 14*x^2 > Out[1]= > 4 2 > Sqrt[1 + 196 x ] == -1 + 12 x - 14 x > > > In[2]:= eqn2 = Thread[(#1^2 & )[eqn1], Equal] > Out[2]= > 4 2 2 > 1 + 196 x == (-1 + 12 x - 14 x ) > > > In[3]:= dummy = Thread[Expand[eqn2], Equal] > Out[3]= > 4 2 2 > 1 + 196 x == (-1 + 12 x - 14 x ) > > > In[4]:= eqn3 = Equal[ eqn2[[1]] , Expand[ eqn2[[2]] ] ] > Out[4]= > 4 2 3 4 > 1 + 196 x == 1 - 24 x + 172 x - 336 x + 196 x > > > In[5]:= Simplify[eqn3] > Out[5]= > 2 > x (6 - 43 x + 84 x ) == 0 > >