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Re: Re: v. 6, third argument to rectangle

• To: mathgroup at smc.vnet.net
• Subject: [mg75849] Re: [mg75845] Re: v. 6, third argument to rectangle
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Sat, 12 May 2007 02:58:28 -0400 (EDT)
• References: <f21e5e$6e7$1@smc.vnet.net> <200705111030.GAA08108@smc.vnet.net>

It's true that it works, but the fact that it works seems to be now  
undocumented. Mathematica 5.2 documentation states:

"In Rectangle[{a, a}, {a, a}, graphics], graphics can be any graphics  
object."

but there does not seem to be any such statement in 6.0 (?)

Andrzej Kozlowski


On 11 May 2007, at 19:30, Jens-Peer Kuska wrote:

> Hi,
>
> that's nonsense  -- Rectangle[] work as in the
> versions before with a third argument.
>
>
> Regards
>    Jens
>
> rip pelletier wrote:
>> hi,
>>
>> thru 5.2 we could display, for example, 2 graphs side-by-side by  
>> using a
>> third argument to Rectangle, the name of a graphics object.
>>
>> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it
>> was a bit of a kludge, and in principle i approve of it going away,
>> but....)
>>
>> what is the replacement?
>>
>> thanks,
>>    rip
>>
>

• References:
  • Re: v. 6, third argument to rectangle
    • From: Jens-Peer Kuska <kuska@informatik.uni-leipzig.de>