Re: v. 6, third argument to rectangle
- To: mathgroup at smc.vnet.net
- Subject: [mg76687] Re: v. 6, third argument to rectangle
- From: dimitris <dimmechan at yahoo.com>
- Date: Sat, 26 May 2007 04:19:24 -0400 (EDT)
- References: <f21e5e$6e7$1@smc.vnet.net>
I think the following was not mentioned.
Since you are interested in putting two graphs side by side what is
bad with the following
In[73]:=
Block[{$DisplayFunction = Identity}, g1 = Plot[o^(1/2), {o, 1, 2},
PlotStyle -> Red];
g2 = Plot[Log[o], {o, 1, 2}, PlotStyle -> Blue]; ]
Show[GraphicsArray[{g1, g2}], ImageSize -> 600]
It works in version 5.2 and I think there will not be any problem in
version 6. (confirmation needed!)
Dimitris
/ rip pelletier :
> hi,
>
> thru 5.2 we could display, for example, 2 graphs side-by-side by using a
> third argument to Rectangle, the name of a graphics object.
>
> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it
> was a bit of a kludge, and in principle i approve of it going away,
> but....)
>
> what is the replacement?
>
> thanks,
> rip
>
> --
> NB eddress is r i p 1 AT c o m c a s t DOT n e t