Re: What is #6 to SphericalPlot3D[]
- To: mathgroup at smc.vnet.net
- Subject: [mg83053] Re: What is #6 to SphericalPlot3D[]
- From: dh <dh at metrohm.ch>
- Date: Fri, 9 Nov 2007 05:09:08 -0500 (EST)
- References: <fguqla$q7h$1@smc.vnet.net>
Hi Roger,
(#6 > 0.95 &) is a function that returns True if its 6'th argument is
bigger than 0.95, False otherwise. If you use:
RegionFunction->(Print[{##}]&) in SpericalPlot3D
you will see that the 6'th argument is the length if the first 3
arguments, I guess the distance from the origin.
hope this helps, Daniel
congruentialuminaire at yahoo.com wrote:
> Hello Mathematica UG:
>
> I was doing some experiments with this function. In the help there is
> an example using RegionFunction -> (#6 > 0.95 &). I cannot find this
> documented anywhere. Is this documented?
>
> I think I remember that there are 6 corrds in a spherical coordinate
> system (or spherical transformation??). If so, is #6 = r cos(theta)?
>
> TIA.
>
> Regards..Roger
>
>