MathGroup Archive 2008

[Date Index] [Thread Index] [Author Index]

Search the Archive

Problem involving NDSolve

  • To: mathgroup at smc.vnet.net
  • Subject: [mg86822] Problem involving NDSolve
  • From: Grandpa <acloninger at wustl.edu>
  • Date: Sat, 22 Mar 2008 00:53:24 -0500 (EST)
  • Organization: The Math Forum

So here's my dilemma.  I am trying to solve a differential equation with complex roots.  Mathematica is taking the incorrect root at certain points when the function crosses over itself.  I generated a set of all points at which this occurs.  The set is 

ProblemList={2.8, 5.599, 8.398}

I now want to use these points in a function.  My function is 

ComplexRoot[t_]:= If[Abs[t - ProblemList[[1]]] > .01 && Abs[t - ProblemList[[2]]] > .01 && Abs[t - ProblemList[[        3]]] > .01, Evaluate[I*(2 + 1/2)(I*x[t])^(1 + 1/2)],   Evaluate[p'[t - .01]]]

The goal here is to have Mathematica take the correct root for all t other than the problem t values, and at those t values simply continue in the direction it was heading previously.  So I want to then plug into the differential equation

solution=NDSolve[{x'[t] == 2p[t], x[0] == 0, p'[t]==ComplexRoot[t], p[0] == 1}, 
{x, p}, {t,0,10}, WorkingPrecision -> 30, MaxSteps -> Infinity][[1]];

and not get an error.  Right now it gives me an error saying that I haven't "literally matched the independent variables." 

If it works, the following graph should have two loops and look like an infinity sign with one of the loops being smaller than the other.

ParametricPlot[{Re[p[t]] /. solution, Im[p[t]] /. solution}, Evaluate[{t,0,10}],PlotRange -> {{-2, 2}, {-2, 2}}]

What can I do to fix this issue?  Any and all help is greatly appreciated.

Thanks,
Alex


  • Prev by Date: Re: Re: Fast way to select those elements from a list
  • Next by Date: Re: Saving Packages
  • Previous by thread: Re: Re: Fast way to select those elements from a list
  • Next by thread: Re: Problem involving NDSolve