Re: simplify polynomial
- To: mathgroup at smc.vnet.net
- Subject: [mg89210] Re: [mg89186] simplify polynomial
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Thu, 29 May 2008 07:05:22 -0400 (EDT)
- References: <200805280847.EAA27235@smc.vnet.net>
On 28 May 2008, at 17:47, vmarian wrote: > I want to simplify a polynomial by factorizing the most of the > terms as possible(that means a product of terms plus a small other > number of terms). I didn't find how to do such incomplete > factorization. Is there a command to do it. Factor works only for > complete factorizations. > > \!\(Simplify[2 - =CE=BB - =CE=BB\^2 - 3\ hmb\ \((\(-2\) + =CE=BB + > =CE=BB\^2)\) + hmb\^3\ \((5 - 12\ =CE=BB + 4\ =CE=BB\^2)\) + hmb\^2\ \((6 - > 3\ =CE=BB - > 8\ =CE=BB\^2 + 2\ =CE=BB\^3)\)]\) > > Thank you. > You have to define uniquely the "factorization" that want. There is nothing in what you write that suggests any kind of unique definition. And if you can't define it in a unique way, you should at least give some criterion which determines what makes a good "factorization" and what does not. For example: (x - 1)*(x - 2) - 1 is always equal to (x - 4)* (x + 1) + 5. So which of these is a better "incomplete factorization" and why? Unless you can provide such information your question does not make sense. Andrzej Kozlowski
- References:
- simplify polynomial
- From: vmarian <vctrmarian@yahoo.com>
- simplify polynomial