Re: Mapping A Condition Across Two Different Lists
- To: mathgroup at smc.vnet.net
 - Subject: [mg91762] Re: [mg91705] Mapping A Condition Across Two Different Lists
 - From: Bob Hanlon <hanlonr at cox.net>
 - Date: Sun, 7 Sep 2008 05:38:01 -0400 (EDT)
 - Reply-to: hanlonr at cox.net
 
targetX = 5; listX = {4, 9, 2, 11, 4};
targetY = 3; listY = {4, 0, 1, 8, 6};
Thread[(targetX > # & /@ listX) &&
  (targetY > # & /@ listY)]
{False,False,True,False,False}
targetX > #[[1]] && targetY > #[[2]] & /@
 Transpose[{listX, listY}]
{False,False,True,False,False}
% == %%
True
Thread[(targetX > # & /@ listX) ||
  (targetY > # & /@ listY)]
{True,True,True,False,True}
targetX > #[[1]] || targetY > #[[2]] & /@
 Transpose[{listX, listY}]
{True,True,True,False,True}
% == %%
True
Bob Hanlon
---- Gregory Lypny <gregory.lypny at videotron.ca> wrote: 
=============
Hello everyone,
Not sure how to do this using Map, or even if it's possible.
I can compare a target value to each value in a list like this.
targetX = 5; listX = {4, 9, 2, 11, 4};
targetX > # & /@ listX
{True, False, True, False, True}
I can do the same for another target and another list.
targetY = 3; listY = {4, 0, 1, 8, 6};
targetY > # & /@ listY
{False, True, True, False, False}
But can I do it in a similar way for the AND or OR condition without  
having to resort to the Table command?
Table[targetX > listX[[i]] && targetY > listY[[i]], {i, Length@listX}]
{False, False, True, False, False}
Table[targetX > listX[[i]] || targetY > listY[[i]], {i, Length@listX}]
{True, True, True, False, True}
Much obliged,
	Gregory
--
Bob Hanlon