Re: complex function fitting?
- To: mathgroup at smc.vnet.net
- Subject: [mg98351] Re: complex function fitting?
- From: dh <dh at metrohm.com>
- Date: Wed, 8 Apr 2009 02:47:49 -0400 (EDT)
- References: <grcgjg$pml$1@smc.vnet.net>
Hi Ned,
Mathematica works by default with complex numbres. E.g. using "Fit":
d = Table[{x + I y, Exp[x + y I ]}, {x, 0, 1, .1}, {y, 0, 1, .1}];
d = Flatten[d, 1];
pol = Fit[d, {1, x, x^2}, x]
yc = pol /. x -> d[[All, 1]];
ListPlot[{Re[#], Im[#]} & /@ (yc - d[[All, 2]]), PlotRange -> All]
Daniel
Ned Lieb wrote:
> Does anyone know how I could extend the domain of Mathematica's
> function-fitting functions so I can use complex-valued data?
>
>
>