Re: ListCurvePathPlot
- To: mathgroup at smc.vnet.net
- Subject: [mg95931] Re: ListCurvePathPlot
- From: Bill Rowe <readnews at sbcglobal.net>
- Date: Fri, 30 Jan 2009 05:43:16 -0500 (EST)
On 1/29/09 at 5:58 AM, djmpark at comcast.net (David Park) wrote:
>I don't understand the new ListCurvePathPlot, which the Help page
>says: "attempts to reconstruct smooth curves defined by the
>specified set of points."
>This plot routine also has the option: InterpolationOrder. And the
>word "Curve" appears not only in the name but repeatedly in the
>descriptions. But look at the following example:
>data = Table[
>RandomReal[{.8, 1.2}] {Cos[t], Sin[t]}, {t, 0, 2 \[Pi] - 2 \[Pi]/6,
>2 \[Pi]/6}];
>ListCurvePathPlot[data,InterpolationOrder -> 3,
>Axes -> False]
>I don't see anything "smooth" or "curvy" about the results!
I am not totally convinced this is a meaningful test example. So
few data points really provide very little information about an
underlying curve. However, there does seem to be a problem with
InterpolationOrder. Contrast the plot you get with the plot
resulting from
LineListPlot[data, InterpolationOrder->3]
Although the resulting curve is not closed, it now has a smooth appearance.
As for your other questions, I don't know the answers and can
only speculate.