Re: countour plot (in 3D)
- To: mathgroup at smc.vnet.net
- Subject: [mg105376] Re: countour plot (in 3D)
- From: dh <dh at metrohm.com>
- Date: Mon, 30 Nov 2009 06:10:41 -0500 (EST)
- References: <heod8g$4du$1@smc.vnet.net>
Claus wrote:
> Hi,
> I have a set of 720 measurements at locations (x,y,z), each associated
> with a value (f).
>
> The y is constant for all locations. So I can generate a ListContourPlot
> quite easily and nicely.
>
> Now I want to show the contour in 3D. This means essentially I want to
> show a contoured plane in 3D. I want to do this in 3D because I want to
> add other sets of measurements which are at different (x,y,z) locations
> (other planes), subsequently.
>
> How can this be done?
>
> I tried ListContourPlot3D, however it tells me this (which I don't
> understand):
>
> ListContourPlot3D::invpts: "\!\(\*
> StyleBox[\"\"\", \"MT\"]\)-- Message text not found --
>
> Can anybody tell what this message means (or what I am doing wrong)?
>
> What excatly can I adjust with the option Contours? The help says "how
> many or what contour surfaces to show". Does that mean, for my first try
> with the one set of 720 measurements I would put Contours->{1}?
>
> Thank you,
> Claus
>
>
>
Hi Claus,
if I understand correctly, you want to project a 2dim graphics onto a
3dim plane.
here is a hack to do this:
we first create the contours:
d = Table[x^2 + y^2, {x, 10}, {y, 10}];
t = ListContourPlot[d];
t[[1]] contains the essential graphics. We the replace every 2dim
coordinate by a three dim coordinate. E.g.:
t[[1]] /. {x_?NumberQ, y_?NumberQ} -> {x, y, 0}
Then we need to tell mathematica that this is a 3dim graohics by wraping
3D around the object:
Graphics3D[t[[1]] /. {x_?NumberQ, y_?NumberQ} -> {x, y, 0} ]
All together for two different planes:
Show[Graphics3D[t[[1]] /. {x_?NumberQ, y_?NumberQ} -> {x, y, 0} ],
Graphics3D[t[[1]] /. {x_?NumberQ, y_?NumberQ} -> {x, y, 10} ]]
Daniel