Re: ReplaceAll and rules from a list v7.0
- To: mathgroup at smc.vnet.net
- Subject: [mg104291] Re: [mg104227] ReplaceAll and rules from a list v7.0
- From: Matthias Greiff <greiff at mac.com>
- Date: Sun, 25 Oct 2009 23:25:47 -0500 (EST)
- References: <200910240640.CAA07557@smc.vnet.net>
Kristoph,
you can define the function and then use the Map-command:
x[{a_, b_}] := a + b
l = {{1, 1}, {2, 2}, {3, 3}}
x /@ l
or
x[{a_, b_}] := a + b
l = {{1, 1}, {2, 2}, {3, 3}}
Map[x, l]
This gives you {2,4,6}.
Best,
Matthias
Am 24.10.2009 um 24. Oktober , 08:40:20 schrieb kristoph:
> Hi,
>
> Suppose I have the equation
>
> x=a+b
>
> and the list
>
> l={{1,1},{2,2},{3,3}}
>
> How can I quickly assign the list to the above equation, that is, I
> would like to get the following result
>
> {2,4,6}
>
> The first element of each sub-list should be assigned to a and the
> second to b.
>
> Thanks in advance.
> Kristoph
>
- References:
- ReplaceAll and rules from a list v7.0
- From: kristoph <kristophs.post@web.de>
- ReplaceAll and rules from a list v7.0