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Re: Transforming a list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg103130] Re: [mg103108] Transforming a list
  • From: Thomas Dowling <thomasgdowling at gmail.com>
  • Date: Wed, 9 Sep 2009 04:40:55 -0400 (EDT)
  • References: <200909080958.FAA26578@smc.vnet.net>

Hello,

lst = {{c, e, g}, {d, f}, {e, g}, {f}, {g}, {}};


In[116]= Flatten[lst, {{2}, {1}}]


Out[116]= {{c, d, e, f, g}, {e, f, g}, {g}}


>From Carl Woll originally, I think.


Good luck

Tom Dowling





On Tue, Sep 8, 2009 at 10:58 AM, Don <donabc at comcast.net> wrote:

> I am given: lst =  {{c, e, g}, {d, f}, {e, g}, {f}, {g}, {}}
>
> I want to form a list of sublists where the first sublist consists of the
> first elements
> from each sublist of lst, the second sublist the second elements from each
> of the sublists of lst etc.
>
> The final outcome should be:
> {{c, d, e, f, g}, {e, f, g}, {g}}
>
> I can do this by first padding the sublists of lst (to make them the same
> length)and then using Transpose. But how to get rid of the trailings 0's?
>
> For example:
>
> newLst = Map[PadRight[#, Length[lst[[1]]]] &, lst]
>
> Transpose[newLst]
>
> which produces:
>
> {{c, d, e, f, g, 0}, {e, f, g, 0, 0, 0}, {g, 0, 0, 0, 0, 0}}
>
> Is there a better way to end up with
>
> {{c, d, e, f, g}, {e, f, g}, {g}}
>
> Thank you.
>
>


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