Re: Re: Output of TraditionalForm for Exp
- To: mathgroup at smc.vnet.net
- Subject: [mg103315] Re: [mg103310] Re: [mg103290] Output of TraditionalForm for Exp
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Tue, 15 Sep 2009 04:24:22 -0400 (EDT)
- Reply-to: hanlonr at cox.net
Alternatively, I get the expected form when I use Simplify on the output of DSolve
Bob Hanlon
---- fizzy <fizzycist at knology.net> wrote:
=============
oops...I goofed...I meant 1/a^2 D[T[t],{t,2}] with the rest the same....
I tried it again with a fresh kernel and, for TraditionalForm, I still get the same form of output of Exp and e^.......however, when I asked for the form of the output in StandardForm then I get the form e^ for the outputs....
jerry blimbaum
----- Original Message -----
From: Bob Hanlon
To: fizzy ; mathgroup at smc.vnet.net
Sent: Sunday, September 13, 2009 8:14 AM
Subject: Re: [mg103290] Output of TraditionalForm for Exp
I get a different (simpler) result.
$Version
7.0 for Mac OS X x86 (64-bit) (February 19, 2009)
eqn = 1/a^2 D[T[t], t] + b D[T[t], t] + c^2 T[t] == 0;
soln = T[t] /. DSolve[eqn, T[t], t][[1]]
C[1]/E^((a^2*c^2*t)/(a^2*b + 1))
eqn /. NestList[D[#, t] &, T[t] -> soln, 1] // Simplify
True
Recommend that you start with a clean kernel.
Bob Hanlon
---- fizzy <fizzycist at knology.net> wrote:
=============
Diff Eqn: 1/a^2 D[T[t],t] + b D[T[t],t] + c^2 T[t] == 0
Solution to this gives the following in TraditionalForm =
output:....V7.01....
C1 Exp[1/2 t (a^2 (-b) - a Sqrt[a^2 b^2 -4 c^2])] + C2 e^(1/2 t =
(Sqrt[a^2 b^2 -4 c^2] - a^2 b)]) .....
where the second part, i.e. e^( )...the exponent part, ( ) , is =
actuallly on the same line as the ^ as it would be if I used the power =
exponent from the Basic Math pallette.....
Q:....why this difference in output??....why arent both 'e' raised to =
the power of, etc??...
I realize I can fix this with a rule and HoldForm but why doesnt =
TradForm use only one of the output forms especially in the same output?
thanks....jerry blimbaum