Re: Replace list element based on a condition how to
- To: mathgroup at smc.vnet.net
- Subject: [mg106662] Re: Replace list element based on a condition how to
- From: dh <dh at metrohm.com>
- Date: Wed, 20 Jan 2010 06:50:12 -0500 (EST)
- References: <hj40od$sfg$1@smc.vnet.net>
Hi Kurt,
without the superfluous braces and a condition on the pattern to prevent
that it matches the whole list it works well:
lst1 /. i_?NumberQ :> fncHourFix[i]
Daniel
Canopus56 wrote:
> Q1. Is there a way to replace a list based on a condition?
>
> I have a list of integers -
>
> lst1 = {18, 19, 20, 21, 22, 23, 0, 1, 2, 3}
>
> that I would like to replace with the following rule -
>
> fncHourFix[h_] := If[(h - 6) < 0, h - 6 + 24, h - 6];
>
> but the replace function -
>
> lst2 = lst1 /. {i_} :> fncHourFix[{i}]
>
> - bombs out.
>
> I've tried several variants.
>
> Any pointers would be appreciated.
>
> Thanks - Kurt
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