Re: plot
- To: mathgroup at smc.vnet.net
- Subject: [mg110707] Re: plot
- From: "David Park" <djmpark at comcast.net>
- Date: Sat, 3 Jul 2010 08:16:03 -0400 (EDT)
I'm not certain of your question. Why don't you just do something like this:
Plot[((2 x + 1) Sqrt[x + 1])/Sqrt[x - 1], {x, 1, 5},
PlotRange -> {Full, {5, 20}},
Frame -> True]
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
From: agua [mailto:auguaylupo at gmail.com]
Hi
With Plot[( (2x+1) Sqrt[x+1] ) / Sqrt[x-1] ,{x,-5,5}]
hoped to obtain a graph only for x>1.
What happened?
regards.