Re: difficulty using FindRoot
- To: mathgroup at smc.vnet.net
- Subject: [mg110237] Re: difficulty using FindRoot
- From: "David Park" <djmpark at comcast.net>
- Date: Thu, 10 Jun 2010 08:06:26 -0400 (EDT)
- References: <4839036.1276083624667.JavaMail.root@n11>
Hello Roger,
It looks to me like there is no root in that region. The nearest approach I
could find was:
f[x_] := 1 + Sum[1/Product[1 - x^i, {i, 1, n}], {n, 1, 100}]
Plot[f[x], {x, 1.0247, 1.0249},
PlotRange -> All,
PlotRangePadding -> Scaled[.1],
Frame -> True,
Axes -> {True, False}, AxesOrigin -> {Automatic, 0},
WorkingPrecision -> 55]
But this function is certainly difficult to explore.
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
From: Roger Bagula [mailto:roger.bagula at gmail.com]
The question of a q-form infinite exponential series
solving to give Pi came up.
I had absolutely no luck with infinite sums on this!
I tried a plot of the function to narrow it down:
Clear[f, x, n, i]
f[x_] := 1 + Sum[1/Product[1 - x^i, {i, 1, n}], {n, 1, 100}]
Plot[f[x], {x, 1.021831198825114750405873564886860549451,
1.02183648425181683450091441045515239239}, PlotRange -> All]
The find root that seemed to work was:
q /. FindRoot[1 + Sum[1/Product[1 -
q^i, {i, 1,
n}], {n, 1, 150}] - Pi == 0, {q,
1.0218701842518167}, WorkingPrecision -> 800,
AccuracyGoal ->
795]
gives:
1.0218311988251147504058736
with error messages:
\!\(Divide::"infy" \(\(:\)\(\ \)\) "Infinite
expression \!\(3.14159265346825122833252`25.0094071873645\/0\) \
encountered."\)
\!\(\*
RowBox[{\(FindRoot::"jsing"\), \(\(:\)\(\ \)\), "\<\"Encountered a
singular
Jacobian at
the point \\!\\({q}\\) = \
\\!\\({1.0218311988251147504058736`25.0094071873645}\\). Try
perturbing the \
initial point(s). \\!\\(\\*ButtonBox[\\\"More=85\\\", \
ButtonStyle->\\\"RefGuideLinkText\\\", ButtonFrame->None, \
ButtonData:>\\\"FindRoot::jsing\\\"]\\)\"\>"}]\)
1 + Sum[1/Product[1 - (1.02183119882511475040587356488686054945)^i,
{i, 1, n}], {n, 1, 150}]
gives
0*10^(-19)
It appears there is no real q such that the sum?
1 + Sum[1/Product[1 - q^i, {i, 1, n}], {n, 1, Infinity}]==Pi
Respectfully, Roger L. Bagula
11759 Waterhill Road, Lakeside,Ca 92040-2905,tel: 619-5610814 :
http://www.google.com/profiles/Roger.Bagula
alternative email: roger.bagula at gmail.com