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Re: What inspite FindInstance ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg108001] Re: [mg107955] What inspite FindInstance ?
  • From: Daniel Lichtblau <danl at wolfram.com>
  • Date: Fri, 5 Mar 2010 04:30:50 -0500 (EST)
  • References: <201003041025.FAA26461@smc.vnet.net>

Artur wrote:
> Dear Mathematica Gurus,
> 
> Mathematical problem is following:
> Find rational numbers a,b,c such that
> (Pi^2)*a+b+c*Catalan==Zeta[2,5/k] for some k
> e.g.
> FindInstance[
>  Zeta[2, 5/4] -a Pi^2 - b - c Catalan == 0, {a, b, c}, Rationals]
> give answer
> FindInstance::nsmet: The methods available to FindInstance are 
> insufficient to find the requested instances or prove they do not exist. >>
> 
> 
> What inspite FindInstance? (I know that we can do 6 loops (3 
> Denominators and 3 Numerators) but we have to have luck to give good 
> range of loops..
> 
> Good answer for my example is {a,b,c}={1,-16,8}but in general case these 
> a,b,c will be rationals (not integers)
> e.g. (Pi^2)*a+b+c*Catalan==Zeta[2,5/2]  we have {a,b,c}={1/2,-40/9,0} 
> but this last case Mathematica deduced autmathically if we execute :
> Zeta[2,5/2]
> first one none.
> 
> Best wishes
> Artur

Here is an approach that involves much less code than what I last sent 
(in the tehcnical sense that "none" is much less than "some").

(1) Go to
http://www.wolframalpha.com

(2) Enter
zeta(2,5/2)
or
zeta(2,5/4)

Results for teh first include a pane
Exact result:
pi^2/2-40/9

Results for the second have a pane
Alternate form:
8 C-16+pi^2

That Wolfram|Alpha is one clever gal.

Daniel Lichtblau
Wolfram Research


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