Re: maximum of a series
- To: mathgroup at smc.vnet.net
- Subject: [mg114022] Re: maximum of a series
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 20 Nov 2010 18:26:33 -0500 (EST)
m[i_, n_] == HoldForm[Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]];
m[i, n]
HoldForm[Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]]
m[3, 5]
HoldForm[Max[Table[Sum[a[k], {k, 3, j}], {j, 3, 5}]]]
% // ReleaseHold
Max[a[3], a[3] + a[4], a[3] + a[4] + a[5]]
Bob Hanlon
---- olfa mraihi <olfa.mraihi at yahoo.fr> wrote:
==========================
Thank you Bob for the reply,
=C2
I tried to use Table but the problem is that I need to use it symbolically =
(without having values for i and n) which means
Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]]
but unfortunately=C2 I=C2 get this error :Iterator {j,i,n} does not hav=
e appropriate bounds
=C2
so how to deal with that?
=C2
Regards,
--- En date de=C2 : Ven 19.11.10, Bob Hanlon <hanlonr at cox.net> a =C3=A9cr=
it=C2 :
De: Bob Hanlon <hanlonr at cox.net>
Objet: Re: [mg113951] maximum of a series
=C3=80: "olfa" <olfa.mraihi at yahoo.fr>, mathgroup at smc.vnet.net
Date: Vendredi 19 novembre 2010, 16h22
m[i_Integer, n_Integer] :==
Max[Table[Sum[a[k], {k, i, j}], {j, i, n}]] /; n >== i
m[3, 5]
Max[a[3], a[3] + a[4], a[3] + a[4] + a[5]]
Bob Hanlon
---- olfa <olfa.mraihi at yahoo.fr> wrote:
==========================
Hi Mathematica Community,
how can I represent for example
the maximum of the summations :sum[a[k],{k,i,j}] where j varies from i
to n?
Thank you
--
Bob Hanlon