Re: Expected value of the Geometric distribution
- To: mathgroup at smc.vnet.net
- Subject: [mg118483] Re: Expected value of the Geometric distribution
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Fri, 29 Apr 2011 07:33:38 -0400 (EDT)
The geometric distribution is discrete (of course), so...
Sum[(1 - p)^k*p*k, {k, 1, Infinity}]
(1 - p)/p
Bobby
On Thu, 28 Apr 2011 05:37:38 -0500, Tonja Krueger <tonja.krueger at web.de>
wrote:
> Hi all,
> I want to calculate expected value of diverse distributions like the
> Geometric distribution (for example).
> As I understand this, the expected value is the integral of the density
> function *x.
> But when I try to calculate this:
> Integrate[(1-p)^k*p*k,k]
> I get this as the answer:
> ((1 - p)^k p (-1 + k Log[1 - p]))/Log[1 - p]^2
> Instead of: (1-p)/p.
> I would be so grateful if someone could explain to me what I'm doing
> wrong.
> Tonja
> ___________________________________________________________
> Empfehlen Sie WEB.DE DSL Ihren Freunden und Bekannten und wir
> belohnen Sie mit bis zu 50,- Euro! https://freundschaftswerbung.web.de
>
--
DrMajorBob at yahoo.com