Re: Inverse Function
- To: mathgroup at smc.vnet.net
- Subject: [mg123609] Re: Inverse Function
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Tue, 13 Dec 2011 05:40:14 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201112121143.GAA12844@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
You realize your equation has precisely THESE variables?
{y, (ax + b)/(cx + d)} // Variables
{ax, b, cx, d, y}
x is not one of them, as you see.
I'll assume you meant
y == (a x + b)/(c x + d);
Solve[%, x]
{{x -> (-b + d y)/(a - c y)}}
Bobby
On Mon, 12 Dec 2011 05:43:50 -0600, Harry Har <harryhar800 at gmail.com>
wrote:
> Hi, All,
>
> I'm newbie in Mathematica. I want to find the inverse function of y=(ax
> +b)/(cx+d). How to to this in Mathematica? Many thank's.
>
> Harry.
>
--
DrMajorBob at yahoo.com
- References:
- Inverse Function
- From: Harry Har <harryhar800@gmail.com>
- Inverse Function