Re: The same function the second time evaluated is faster. Why?
- To: mathgroup at smc.vnet.net
- Subject: [mg119109] Re: The same function the second time evaluated is faster. Why?
- From: Bill Rowe <readnews at sbcglobal.net>
- Date: Sun, 22 May 2011 06:53:53 -0400 (EDT)
On 5/21/11 at 6:47 AM, guillermo.sanchez at hotmail.com (Guillermo
Sanchez) wrote:
>I evaluate the below function ,
>Int[1]:=1+1
>Int[2]:=Timing[(f2[x1_] := Integrate[Sin[x^3], {x, 0, x1}];
>f2[Range[10]]);]
>Out[2]:= {12.261, Null}
>I repeat the evaluation is faster
>Out[2]:={1.389, Null}
>and the third faster
>Out[3]:= {0.281, Null}
>Even writting f3 instead f2
>Timing[(f3[x1_] := Integrate[Sin[x^3], {x, 0, x1}]; f3[Range[10]]);]
>{0.281, Null}
>Why the second and third evaluation are faster?
Mathematica caches intermediate results. So, the second and
third evaluations use the cached results from previous
computations to save time.