Re: Series[log[x], {x, 0, 3}]
- To: mathgroup at smc.vnet.net
- Subject: [mg119103] Re: Series[log[x], {x, 0, 3}]
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Sun, 22 May 2011 06:52:46 -0400 (EDT)
The function is called Log. (ALL Mathematica built-ins start with capital
letters.)
Log has a singularity at 0, so you'd have to expand around some other
point, such as 1:
Series[Log@x, {x, 1, 3}]
(x-1)-1/2 (x-1)^2+1/3 (x-1)^3+O[x-1]^4
Bobby
On Sat, 21 May 2011 05:44:59 -0500, Hongyi Zhao <hszhao.cn at gmail.com>
wrote:
> Hi all,
>
> I do the following computation within Mathematica:
>
> Series[log[x], {x, 0, 3}]
>
> Then I get:
>
> log[0]+(log^\[Prime])[0] x+1/2 (log^\[Prime]\[Prime])[0] x^2+1/6
> (log^(3))
> [0] x^3+O[x]^4
>
> Any hints on this result? The log[0] is illegal in my mind.
>
> Regards.
> --
> .: Hongyi Zhao [ hongyi.zhao AT gmail.com ] Free as in Freedom :.
>
--
DrMajorBob at yahoo.com