Re: get a, b from numbers in the form a+b Pi
- To: mathgroup at smc.vnet.net
- Subject: [mg119197] Re: get a, b from numbers in the form a+b Pi
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Tue, 24 May 2011 06:00:15 -0400 (EDT)
The code
List@@#/{1,Pi}&/@Expand@nums
fails if entries a + b Pi in the list nums includes have a = 0 or b = 0.
On 5/23/2011 6:24 AM, Ray Koopman wrote:
> On May 22, 3:58 am, "1.156"<r... at piovere.com> wrote:
>> I have lists of numbers (Mathematica output) all numerically in the
>> form a + b*Pi and I'm trying to extract the values of a and b for
>> further work.
>>
>> Here's an example of the best I've been able to do so far:
>>
>> nums={1/2 (-2+\[Pi]),-2+(3 \[Pi])/4,-(11/3)+(5 \[Pi])/4,5/48 (-64+21
>> \[Pi]),-(61/5)+(63 \[Pi])/16,-(338/15)+(231 \[Pi])/32};
>> {FullForm[#][[1,1]],FullForm[#][[1,2]]/\[Pi]}&/@nums
>>
>> When I run this line of code 4 of the six input numbers give me the
>> {a,b} I'm looking for but the first and fourth entries fail because the
>> form isn't right. Possibly I could patch this scheme to look for a small
>> finite set of possibilities of input number form but I suspect I may a
>> long way from attacking this problem correctly.
>>
>> Can someone offer some other ideas on how to pull this off? Many thanks
>> for looking at this. Rob
>> --
>> Sent from my plain desktop PC.
>
> You need to Expand nums to get the terms into the form a + b*Pi.
> Also, you can use Apply to change the Plus heads to List.
>
> List@@#/{1,Pi}&/@Expand@nums
>
--
Murray Eisenberg murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305