Re: How to do quickest
- To: mathgroup at smc.vnet.net
- Subject: [mg123054] Re: How to do quickest
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Tue, 22 Nov 2011 05:33:20 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201111210929.EAA14830@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
Here's your code timed with an upper limit of 3000:
Timing[Do[y = Round[Sqrt[x^3]];
If[(x^3 - y^2) != 0,
kk = m /.
Solve[{4 m^2 + 6 m n + n^2 ==
x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}][[1]];
ll = CoefficientList[MinimalPolynomial[kk][[1]], #1];
lll = Length[ll];
If[lll < 12, Print[{x/(x^3 - y^2)^2, kk, x, y, x^3 - y^2}];
If[Length[ll] == 3, Print[{kk, x, y}]]]], {x, 2, 3000}]]
{971/1377495072,3 Sqrt[2/5],1942,85580,52488}
{3 Sqrt[2/5],1942,85580}
{1439/117596448,Sqrt[2],2878,154396,15336}
{Sqrt[2],2878,154396}
{187.257, Null}
This is better:
Clear[x, y]
kk = m /.
First@Solve[{4 m^2 + 6 m n + n^2 ==
x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}];
Timing[qq = First@Last@Reap@Do[y = x^3 // Sqrt // Round;
(x^3 - y^2) != 0 &&
Length@CoefficientList[MinimalPolynomial[kk][z], z] < 12 &&
Sow@{x, y, kk, len}, {x, 2, 3000}]]
{14.0493, {{1942, 85580, -3 Sqrt[2/5], 13}, {2878, 154396, -Sqrt[2],
13}}}
And this, even better:
Clear[x, y]
kk = m /.
First@Solve[{4 m^2 + 6 m n + n^2 ==
x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}];
Timing[qq =
First@Last@
Reap@Do[SquareFreeQ@x && (y = x^3 // Sqrt // Round; True) &&
Length@CoefficientList[MinimalPolynomial[kk][z], z] < 12 &&
Sow@{x, y, kk, len}, {x, 2, 3000}]]
{8.39548, {{1942, 85580, -3 Sqrt[2/5], 13}, {2878, 154396, -Sqrt[2],
13}}}
All this is VERY slow nonetheless. Maybe there's another way to
characterize the problem?
Bobby
On Mon, 21 Nov 2011 03:29:38 -0600, Artur <grafix at csl.pl> wrote:
> Dear Mathematica Gurus,
> How to do quickest following procedure (which is very slowly):
>
> qq = {}; Do[y = Round[Sqrt[x^3]];
> If[(x^3 - y^2) != 0,
> kk = m /. Solve[{4 m^2 + 6 m n + n^2 ==
> x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}][[1]];
> ll = CoefficientList[MinimalPolynomial[kk][[1]], #1];
> lll = Length[ll];
> If[lll < 12, Print[{x/(x^3 - y^2)^2, kk, x, y, x^3 - y^2}];
> If[Length[ll] == 3, Print[{kk, x, y}]]]], {x, 2, 1000000}];
> qq
>
>
> (*Best wishes Artur*)
>
--
DrMajorBob at yahoo.com
- References:
- How to do quickest
- From: Artur <grafix@csl.pl>
- How to do quickest