Re: count zeros in a number
- To: mathgroup at smc.vnet.net
- Subject: [mg121827] Re: count zeros in a number
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Tue, 4 Oct 2011 01:31:37 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <j69104$rda$1@smc.vnet.net> <201110030822.EAA08807@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
But the answer is 55, not 62. z = 24^24*55^55; Length[Split[IntegerDigits[z]][[-1]]] 55 Bobby On Mon, 03 Oct 2011 03:22:37 -0500, Dr. Wolfgang Hintze <weh at snafu.de> wrote: > > "dimitris" <dimmechan at yahoo.com> schrieb im Newsbeitrag > news:j69104$rda$1 at smc.vnet.net... >> Hello. >> >> Consider e.g. the number 24^24*55^55. >> This number ends with exactly 55 zeros as the following demonstrate >> >> In[201]:= Mod[24^24*55^55, 10^55] >> Mod[24^24*55^55, 10^56] >> >> Out[201]= 0 >> Out[202]= 20000000000000000000000000000000000000000000000000000000 >> >> >> What I want now is a way to count the zeros that a number ends >> without >> knowing in advance this number of zeros like in the above example. >> >> Thanks in advance. >> Dimitris >> > You can use the function > > f[z_]:=Length[Split[IntegerDigits[z]][[-1]]] > z = 24^24*55^55; > f[z] > 62 > > Wolfgang > > -- DrMajorBob at yahoo.com
- References:
- Re: count zeros in a number
- From: "Dr. Wolfgang Hintze" <weh@snafu.de>
- Re: count zeros in a number