Re: Simplifying expressions using rules with recursion
- To: mathgroup at smc.vnet.net
- Subject: [mg127612] Re: Simplifying expressions using rules with recursion
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Tue, 7 Aug 2012 03:02:47 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <20120806083648.8090367FE@smc.vnet.net>
expr = A.B.A + C.A.B.A; expr /. A.B.A -> A A + C.A Bob Hanlon On Mon, Aug 6, 2012 at 4:36 AM, <wimmer.mike at googlemail.com> wrote: > I would like to use Mathematica to simplify a long expression consisting of tems of products of matrices. These matrices obey equations of the form A = A.B.A, and I would like Mathematica to use these identities to simplify my expression. > How can I tell Mathematica to do that? Just entering > > [1]: A = A.B.A > > does not work, as Mathematica will complain about too man recursions (which I understand). But how do > I do it properly? >
- References:
- Simplifying expressions using rules with recursion
- From: wimmer.mike@googlemail.com
- Simplifying expressions using rules with recursion