Squares in Q[r], a question about algebraic numbers in mathematica
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- Subject: [mg127632] Squares in Q[r], a question about algebraic numbers in mathematica
- From: Kent Holing <KHO at statoil.com>
- Date: Wed, 8 Aug 2012 03:18:45 -0400 (EDT)
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The code below confuses me:
I thought that it should return for example (r^2+1)^2 when applied to (r^2+1)^2 whatever a is.
The code is supposed to do the following:
Given an element p (say polynomial) in Q[r] for a root r of a given polynomial in Q[x], the code should return p as q^2 for q the square root q of p as an element (polynomial) of Q[r] if q exists.
But, it does not! When applied to (r2+1)^2 it returns in fact (r^2/16+1)^2, using r/4 instead of r?
The code:
SquareQrQ[a_,u_]:=Head@ToNumberField[Sqrt@u,a] === AlgebraicNumber//Quiet;
SqrtQr[a_,p_]:=Module[{f,q},
f=Check[ToNumberField[Sqrt[p//Expand],a],"non-square"]//Quiet;
q=AlgebraicNumberPolynomial[f,r]//Quiet;
Plus[q]^2];
sq[a_,p_]:=SqrtQr[a,p];
If
a=Root[x^4+5/8x^2+5/8x+205/256,x,1];
then
sq[a,(r^2+1)^2/.r->a] returns (r^2/16+1)^2, not (r^2+1)^2.
Any comments are highly appreciated.
Kent Holing, Norway
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- Squares in Q[r], a question about algebraic numbers in mathematica
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- Squares in Q[r], a question about algebraic numbers in mathematica