Re: Thread::tdlen: Objects of unequal length in

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• Subject: [mg127772] Re: Thread::tdlen: Objects of unequal length in
• From: Aaron Sokolik <aaron.sokolik at gmail.com>
• Date: Mon, 20 Aug 2012 21:31:04 -0400 (EDT)
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```Thanks for the help.  Everything works with the "First" wrapper.

On Mon, Aug 20, 2012 at 8:35 AM, Sseziwa Mukasa <mukasa at gmail.com> wrote:

> The {} indicate a list, but lists can be nested so a structure of the form
> {{...}} is a list of length one whose first element is another list.  I'm
> not sure what you are after with the MapThread[Mean,
> Sequence[{{testdata}}]] expression, my guess is you're computing the mean
> along the rows of an array.  Assuming your data is in a 2D array then
> Last[testdata] is the last row of your data and what you expect is the
> number of columns (length of last row) to be the same as the number of
> computed means.
>
> Assuming you want the means along the rows I would have done:
> Mean/@Transpose[testdata] (/@ is the infix form of Map so this is
> equivalent to Map[Mean,Transpose[testdata]]) which is probably easier to
> interpret.  Otherwise, just take the first element of the result of your
>
> Regards,
>         Sseziwa
>
> On Aug 20, 2012, at 4:14 AM, Aaron wrote:
>
> > I'm new to Mathematica and trying to run rebuild some programs from
> other systems in Mathematica.  I'm operating on large data lists and
> receiving the unequal length error.  However, if I simply paste the output
> without the extra curly bracket into an operation, everything works.
>  Obviously, copying and pasting wont work for functions... How can I get
> around this?
> >
> > Below are the functions I'm using to generate two lists from a single
> dataset:
> >
> > Out[13]= {{15.0059, 14.9897, 15.0248,....}}
> >
> > ln[14]:= Last[testdata]
> > Out[14]= {14.9602, 14.8624, 15.3364, 15.0231,....}
> >
> > When I run Length on each of the outputs, I receive the proper number of
> datapoints for the Last function but receive an output of "1" for the Mean
> function.  If I paste the output with only 1 "{" though and run Length, I
> >
> > I know this must be simple but I'm stuck.
> >
>
>

```

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