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Re: Find the value of x & y

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  • Subject: [mg127828] Re: Find the value of x & y
  • From: psycho_dad <s.nesseris at gmail.com>
  • Date: Sat, 25 Aug 2012 04:25:00 -0400 (EDT)
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Hey,

You can use the following code to search numerically as I don't think this equation can be solved analytically.

eq=16^(x^2+y)+16^(y^2+x)-1;
Plot3D[eq==0,{x,-2,1},{y,-2,1}]
FindRoot[(eq/.x->-1/2)==0,{y,-1/3}]
Manipulate[ContourPlot[eq==a,{x,-2,1},{y,-2,1}],{{a,1},0,5,0.1}]

I won't put my hand in the fire, but I think that your equation is satisfied only by one point. If you change the constant, then you can plot the contours.

Cheers

PS Check the Mathematica help for details on the functions.



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