Re: coloring individual hexagons in a grid...
- To: mathgroup at smc.vnet.net
- Subject: [mg127889] Re: coloring individual hexagons in a grid...
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Thu, 30 Aug 2012 04:08:46 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <20120828085302.9525568C1@smc.vnet.net>
Hexagon[x_] := Line[x + # & /@ (Through[{Cos, Sin}[Pi #/3]] & /@ Range[0, 6])] HexagonalGrid[nbrRows_, nbrColumns_, colorFunction_: Null] := Module[{i, j}, Table[{ If[colorFunction === Null, Black, colorFunction[i, j]], Hexagon[ {3/2 j, Sqrt[3] i + Mod[j, 2] Sqrt[3]/2}]}, {i, nbrRows}, {j, nbrColumns}]] With[{k = 3}, Show[Graphics[ HexagonalGrid[k, k]], AspectRatio -> Automatic]] With[{k = 3}, Show[Graphics[ HexagonalGrid[k, k, Hue[ Rescale[#1 + #2, {2, 2 k}]] &], AspectRatio -> Automatic]]] Bob Hanlon On Tue, Aug 28, 2012 at 4:53 AM, Richard Palmer <rhpalmer at gmail.com> wrote: > > I am using the code shown below to draw square hexagonal grids. > > Hexagon[x_]:=Line[x+#&/@(Through[{Cos,Sin}[Pi #/3]]&/@Range[0,6])] > > HexagonalGrid[x_,y_]:=Module[{i,j}, > Table[Hexagon[{3/2i,Sqrt[3]j+Mod[i,2]Sqrt[3]/2}],{i,x},{j,y}] > ] > > k; > Show[Graphics[HexagonalGrid[k,k]], > AspectRatio->Automatic] > > How does one assign a color to individual cells in the hex grid? > -- > Richard Palmer > > Home 941 412 8828 > Cell 508 982-7266 > >
- References:
- coloring individual hexagons in a grid...
- From: Richard Palmer <rhpalmer@gmail.com>
- coloring individual hexagons in a grid...