Re: Some assistance from seasoned users.
- To: mathgroup at smc.vnet.net
- Subject: [mg124928] Re: Some assistance from seasoned users.
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Sun, 12 Feb 2012 05:05:31 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201202111135.GAA16372@smc.vnet.net>
Judging from your question, perhaps you are using the wrong syntax
Integrate[Sin[x]^3/x, {x, 0, Infinity}]
Pi/4
Integrate[Sin[x]^3/x^3, {x, 0, Infinity}]
(3*Pi)/8
Bob Hanlon
On Sat, Feb 11, 2012 at 6:35 AM, peter livingston
<peter.livingston at cox.net> wrote:
> Folks!
>
>
>
> I have recently come to the pleasures of Mathematica from other popular but
> very expensive programming methods that I, as a retiree, cannot afford.
>
>
>
> My specific question is this: why am I able to get Mathematica to do the
> complete integral of sin(x)/x, but it refuses to do any of the other types:
> specifically sin^3[x]/x or sin^3[x]/x^3 over the half interval from zero to
> infinity. (see page 449 of G & R Table of Integrals).
>
>
>
> It seems to suggest that throwing away my Gradshtein and Ryzhik is premature
> in spite of the claims in the Mathematica "Mathematics and Algorithms"
> manual.
>
>
>
> Peter Livingston
- References:
- Some assistance from seasoned users.
- From: "peter livingston" <peter.livingston@cox.net>
- Some assistance from seasoned users.