Re: Simplification de formule/ Simplification of formula
- To: mathgroup at smc.vnet.net
- Subject: [mg124434] Re: Simplification de formule/ Simplification of formula
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Thu, 19 Jan 2012 05:14:48 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201201181104.GAA16719@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
-((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[
a2 - aV2])/(DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3])) + (KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[
a2 - aV2])/(DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3]) - (DG3 P3 Sin[alpha3] Sin[
a2 - aV2])/(DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3]) - (DK FV2 Pv2 Cos[a2 - alpha3] Cos[
a2 - aV2] Sin[
aV2])/(L2 (DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3])) + (FV2 KF Pv2 Cos[a2 - aV2] Sin[
a2 - alpha3] Sin[
aV2])/(L2 (DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3])) - (KF Pv2 Cos[a2 - alpha3] Sin[
a2 - aV2] Sin[aV2])/(DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3]) + (FV2 KF Pv2 Cos[a2 - alpha3] Sin[
a2 - aV2] Sin[
aV2])/(L2 (DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3])) - (DK Pv2 Sin[a2 - alpha3] Sin[
a2 - aV2] Sin[aV2])/(DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3]) + (DK FV2 Pv2 Sin[a2 - alpha3] Sin[
a2 - aV2] Sin[
aV2])/(L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) //
TrigExpand // FullSimplify
-(FV2 KF Pv2 Cos[2 a2 - alpha3] - KF L2 Pv2 Cos[alpha3] -
FV2 KF Pv2 Cos[2 a2 - alpha3 - 2 aV2] +
KF L2 Pv2 Cos[2 a2 - alpha3 - 2 aV2] +
DG3 L2 P3 Cos[a2 - alpha3 - aV2] -
DG3 L2 P3 Cos[a2 + alpha3 - aV2] + DK FV2 Pv2 Sin[2 a2 - alpha3] +
DK L2 Pv2 Sin[alpha3] +
DK (-FV2 + L2) Pv2 Sin[
2 a2 - alpha3 - 2 aV2])/(2 L2 (DK Cos[a2 - alpha3] -
KF Sin[a2 - alpha3]))
Bobby
On Wed, 18 Jan 2012 05:04:01 -0600, Nicolas Simon
<nicodumonastal at gmail.com> wrote:
>
> Hi !
>
> I want to simplify this formula :
>
> -((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (
> KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (
> DG3 P3 Sin[alpha3] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (
> DK FV2 Pv2 Cos[a2 - alpha3] Cos[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (
> FV2 KF Pv2 Cos[a2 - aV2] Sin[a2 - alpha3] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (
> KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (
> FV2 KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (
> DK Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (
> DK FV2 Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])).
>
> By manually regrouping the terms, the denominator disappears for a
> large number of fraction but I'm not able to reproduce this result
> with Simplify or others Mathematica tools to handle formula. Any
> suggestion of how I could do that with Mathematica ?
> Thank you for your help !
>
>
>
>
>
>
>
>
>
> Bonjour,
>
> Je souhaite simplifier cette formule :
>
> -((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (
> KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (
> DG3 P3 Sin[alpha3] Sin[a2 - aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (
> DK FV2 Pv2 Cos[a2 - alpha3] Cos[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (
> FV2 KF Pv2 Cos[a2 - aV2] Sin[a2 - alpha3] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (
> KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (
> FV2 KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (
> DK Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (
> DK FV2 Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/(
> L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])).
>
> En regroupant les bons termes le d=E9nominateur se simplifie pour un
> grand nombres de fractions mais je n'arrive pas a ce r=E9sultat avec les
> outils de simplification (FullSimplify ou Simplify) ou les outils de
> manipulations de formule. Est ce que vous auriez une id=E9e de comment
> faire comme pr=E9ciser certains "assumption" dans Simplify ?
> Merci de votre aide.
>
--
DrMajorBob at yahoo.com
- References:
- Simplification de formule/ Simplification of formula
- From: Nicolas Simon <nicodumonastal@gmail.com>
- Simplification de formule/ Simplification of formula