Re: Using Fit to interpolate data
- To: mathgroup at smc.vnet.net
- Subject: [mg127447] Re: Using Fit to interpolate data
- From: "Kevin J. McCann" <kjm at KevinMcCann.com>
- Date: Wed, 25 Jul 2012 02:34:36 -0400 (EDT)
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Kris,
This is a follow up to my earlier post. If you do a plot of {x,Log[y]}
of your data. You will see a very good fit to a straight line (if you
drop the first point). This suggests that you do a nonlinear fit to an
exponential or a linear fit to the log.
Kevin
fiberDataDensitiesFeierabend = {{16, 0}, {10.7, 0.11}, {10.4,
0.19}, {9.77, 0.41}, {8.29, 3.05}, {7.14, 19.86}};
data2 = ({#[[1]], Log[#[[2]]]} &) /@ fiberDataDensitiesFeierabend
data2 = Drop[data2, 1]
p1 = ListPlot[data2, PlotRange -> All]
f[x_] = Fit[data2, {1, x}, x]
p2 = Plot[f[x], {x, 7, 11}, Epilog -> p1[[1]]]
On 7/24/2012 4:16 AM, Kris Carlson wrote:
> Hi,
>
> Can someone enlighten me about how to fit a curve to data? These data are
> of the density of axons of given diameters in the spinal cord. The density
> of smaller fibers is dramatically larger than that of larger fibers. There
> cannot be density < 0 of any diameter, so heuristically to prevent a fit
> yielding an equation that dips below 0 I added an end point with fiber
> diameter = 16 that is 0. Then using Fit I try to increase the exponent of x
> until the curve doesn't yield negative values. The fit looks good in large
> scale but when I plot the region of greatest interest, 8 < x < 14, it no
> longer looks so good. Maybe I am simply ignorant about fitting a curve to
> somewhat irregular data? Or can it be done?
>
> Thank you.
>
> Kris
>
> fiberDataDensitiesFeierabend = {{16, 0}, {10.7, 0.11}, {10.4,
> 0.19}, {9.77, 0.41}, {8.29, 3.05}, {7.14, 19.86}};
>
> fbddPlot =
> ListPlot[fiberDataDensitiesFeierabend,
> PlotMarkers -> {Automatic, Medium}]
>
> fbddFit = Fit[fiberDataDensitiesFeierabend, {1, x, x^-13}, x]
>
> Show[Plot[fbddFit, {x, 4, 20},
> PlotRange -> {{4.5, 20}, {-0.5, 25}}], fbddPlot]
>
> Show[Plot[fbddFit, {x, 4, 28},
> PlotRange -> {{8, 16}, {-0.5, 1}}], fbddPlot]
>
>