Re: Approximate Zero Times A Symbol
- To: mathgroup at smc.vnet.net
- Subject: [mg127072] Re: Approximate Zero Times A Symbol
- From: Christoph Lhotka <christoph.lhotka at fundp.ac.be>
- Date: Thu, 28 Jun 2012 04:02:43 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201206270811.EAA18698@smc.vnet.net>
Hello,
My argumentation would be as follows:
0 x = 0 if (0,x) have infinite precision, while 0. x = 0. since the
result has a precision at most of 0.,
therefore there is no need to keep the x, which has infinite precision:
for the expression we only
need x up to precision of 0., therefore 0. * approximate x = 0., which
is true up to the precision
of 0.
If I understand well, what you would like to have and if it only
concerns the format it is printed,
I would define:
dis[ex_]:=Plus@@({x,y}*(StringTrim/@ToString/@(PaddedForm[Coefficient[ex,#],{8,8}]&/@{x,y})))
which would give
dis/@{0.x+1.y,0.34324324324324324324324x+1.000000000004y}
{0.00000000 x+1.00000000 y,0.34324324 x+1.00000000 y}
Hope that helps,
Christoph
On 06/27/2012 10:11 AM, djmpark wrote:
> What is the justification for the following?
>
>
>
> 0. x + 1. y
>
>
>
> 0. + 1. y
>
>
>
> I want to display a dynamic weighted sum of x and y and sometimes one of the
> coefficients becomes zero. I would like to keep both terms (for a steady
> display) and format with NumberForm. If Mathematica is going to drop the x,
> why doesn't it at least also drop the approximate zero?
>
>
>
> If I use SetPrecision we obtain:
>
>
>
> SetPrecision[0. x + 1. y, 10]
>
>
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> 1.000000000 y
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>
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> which is at least more consistent, but not what I want either.
>
>
>
> David Park
>
> djmpark at comcast.net
>
> http://home.comcast.net/~djmpark/index.html
>
- References:
- Approximate Zero Times A Symbol
- From: "djmpark" <djmpark@comcast.net>
- Approximate Zero Times A Symbol