Re: Fourier DFT scaling problem

• To: mathgroup at smc.vnet.net
• Subject: [mg126606] Re: Fourier DFT scaling problem
• From: Dana DeLouis <dana01 at me.com>
• Date: Fri, 25 May 2012 04:54:25 -0400 (EDT)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com

```> FourierTransform[Psi[x], x, k]
>
> OUT: (Pi^(-1/4)) (E^(-k^2/2))

Hi.  I don't have a solution, but does anything here help?
Does changing the default settings help in some way?

xData={-1,+1};
xSignal={+1,-1};
xDefault = {0,1};

Psi[x_] := (Pi^(-1/4)) (E^(-x^2/2))

SetOptions[{FourierTransform,InverseFourierTransform},FourierParameters->xDefault];

FourierTransform[Psi[x],x,k]
E^(-(k^2/2))/\[Pi]^(1/4)

SetOptions[{FourierTransform,InverseFourierTransform},FourierParameters->xSignal];

FourierTransform[Psi[x],x,k]
Sqrt[2] E^(-(k^2/2)) \[Pi]^(1/4)

SetOptions[{FourierTransform,InverseFourierTransform},FourierParameters->xData];

FourierTransform[Psi[x],x,k]
E^(-(k^2/2))/(Sqrt[2] \[Pi]^(3/4))

= = = = =
Dana DeLouis
Mac & Math 8
= = = = =

On May 22, 5:20 am, Arthur <art... at ymail.com> wrote:
> Hi all.
>
> I hope someone can help me with what seems to be a fairly elementary problem, nevertheless I have spent a good deal of time trying to come to a solution without any success. I am fairly new to the Fourier transform.
>
> My problem is that the output of the Fourier[] command has a scaling dependency on my sampling parameters which I cannot figure out how to remove.
>
> In general I have a numerical function Psi[x] (a wavefunction) and I would like to compute an approximation to the Fourier transform F[Psi[x]] ~~ Psihat[k].
>
> I am assuming the best way to achieve this is using the built in Fourier[] function.
>
> Now although I expect to have a numerical function Psi[x] my problem is apparent even when I define Psi[x] analytically.
>
> If I have
>
> Psi[x_] := (Pi^(-1/4)) (E^(-x^2/2))
>
> and take the continuous FT
>
> FourierTransform[Psi[x], x, k]
>
> OUT: (Pi^(-1/4)) (E^(-k^2/2))
>
> The output is as expected an identical function of k (since Psi[x] was a normalized eigenfunction of the FT).
>
> If I try to take the DFT of Psi[x] however:
>
> /******CODE******/
>
> n1 = 2^8.; (* sampling points *)
> L = 32.; (* domain [-L/2,L/2] *)
> dx = L/n1; (*step size*)
>
> X = Table[-dx n1/2 + (n - 1) dx, {n, n1}]; (* lattice *)
>
> rot[X_] := RotateLeft[X, n1/2]; (* rotate input/output of fourier *)
> F[X_] := rot@Fourier@rot@X; (* DFT *)
>
> SetOptions[ListLinePlot, PlotRange -> {{-L/2, L/2}, {0, 1}},
>  DataRange -> {-L/2, L/2}, Filling -> Axis];
>
> ListLinePlot[Abs[Psi[X]]^2]
> ListLinePlot[Abs[F@Psi[X]]^2]
>
> /******END******/
> The second graph of the squared modulus of F@Psi[X] is evidently incorrectly scaled. Moreover this scaling error is not improved by increasing the sampling frequency, and is in fact exacerbated by it.
>
> It seems reasonable that the scaling be dependent on the value dx, though I have done a lot of experimentation with the FourierParameters command to remove this dependence though I can't get it to work in a way that is independent of the choice of Psi[x].
>
> Any help would be *greatly* appreciated!
>
> Thanks and best regards,
>
> Arthur

```

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