Re: Numerical expression

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• Subject: [mg128798] Re: Numerical expression
• From: Bob Hanlon <hanlonr357 at gmail.com>
• Date: Tue, 27 Nov 2012 03:31:09 -0500 (EST)
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• References: <20121126042617.44760687B@smc.vnet.net>

```This does not appear to equal one. Assuming that the exponents are
intended to be rational and that the parentheses are balanced as
follows

expr = ((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) +
(9 (3)^(1/2) + 4 (23)^(1/2))^(1/3))/(3)^(1/2)

(2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/
Sqrt[3]

expr // FullSimplify

1 + Sqrt[23/3]

expr // N

3.76887

Bob Hanlon

On Sun, Nov 25, 2012 at 11:26 PM, Massimo <linusx++ at mail.com> wrote:
> How could I handle in Mathematica this expression?
>
> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3  )  /  (3)^1/2)
>
> With a lot of trouble I have found out that is equal 1,
> but how to get it with Mathematica?
>
> Thanks very much.
>
>
>
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```

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