Re: Sum command
- To: mathgroup at smc.vnet.net
- Subject: [mg128016] Re: Sum command
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Sun, 9 Sep 2012 05:09:06 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <20120908070808.4AD8D683B@smc.vnet.net>
iSum[expr_,
{x_Symbol, xmin_, xmax_, xstep_Integer: 1}] :=
Sum[expr, {x, Ceiling[xmin], Floor[xmax], xstep}]
iSum[f[i], {i, 7/2, 4}]
f[4]
iSum[f[i], {i, 3/2, 2}]
f[2]
iSum[f[i], {i, 1/2, 9/2}]
f[1] + f[2] + f[3] + f[4]
iSum[f[i], {i, 1/2, 9/2, 2}]
f[1] + f[3]
Bob Hanlon
On Sat, Sep 8, 2012 at 3:08 AM, Rodrigo AP <digorna at gmail.com> wrote:
>
> Dear group,
>
> How could I get: Sum[f[i],{i,7/2,4}]=f[4] or Sum[f[i],{i,3/2,2}]=f[2] ? I
> mean, I want the iterator running over the integers only ...
>
> Regards
>
> --
> Rodrigo
>
- References:
- Sum command
- From: Rodrigo AP <digorna@gmail.com>
- Sum command